Classical Process Synchronization Problems
Process synchronization plays a crucial role in multi-process systems, ensuring data integrity and preventing conflicts. Several classic problems illustrate real-world challenges where synchronization techniques are necessary.
1. Producer-Consumer Problem
Scenario:
A producer generates data and places it into a buffer, while a consumer retrieves and processes it. The challenge is ensuring that:
- The producer does not overwrite an already filled buffer.
- The consumer does not read empty data.
Solution Using Semaphores
This problem is solved using two semaphores:
- Full → Tracks the number of items in the buffer.
- Empty → Tracks available slots for new items.
semaphore empty = buffer_size;
semaphore full = 0;
mutex lock;
Producer() {
while (true) {
wait(empty); // Ensure buffer has space
wait(lock); // Lock access
buffer.push(item); // Add item
signal(lock);
signal(full); // Notify consumer
}
}
Consumer() {
while (true) {
wait(full); // Ensure data is available
wait(lock); // Lock access
item = buffer.pop(); // Retrieve item
signal(lock);
signal(empty); // Notify producer
}
}
🔹 Used in: Multi-threaded applications, data streaming, request handling in web servers.
2. Reader-Writer Problem
Scenario:
- Multiple readers can access shared data simultaneously.
- Only one writer can modify data, ensuring consistency.
Solution Using Read-Write Locks
This is solved by prioritizing either readers or writers using read-write locks.
mutex write_lock;
int read_count = 0;
mutex read_lock;
Reader() {
while (true) {
wait(read_lock);
read_count++;
if (read_count == 1) wait(write_lock);
signal(read_lock);
// Read data...
wait(read_lock);
read_count--;
if (read_count == 0) signal(write_lock);
signal(read_lock);
}
}
Writer() {
while (true) {
wait(write_lock);
// Modify data...
signal(write_lock);
}
}
🔹 Used in: Databases, logging systems, filesystem read-write access.
3. Dining Philosophers Problem
Scenario:
Five philosophers sit around a table, each needing two forks to eat. The challenge is ensuring that:
- Philosophers don’t hold one fork indefinitely, causing deadlocks.
- They alternate eating and thinking to avoid starvation.
Solution Using Mutexes
A deadlock-free approach is ensuring only four philosophers can pick up forks at the same time.
mutex fork[5];
Philosopher(int i) {
while (true) {
think();
wait(fork[i]);
wait(fork[(i + 1) % 5]);
eat();
signal(fork[i]);
signal(fork[(i + 1) % 5]);
}
}
🔹 Used in: Multithreading resource allocation, cloud-based task scheduling.
Conclusion
Synchronization problems like Producer-Consumer, Reader-Writer, and Dining Philosophers illustrate real-world concurrency challenges. Using mechanisms like semaphores, mutexes, and read-write locks, developers can prevent deadlocks, optimize resource allocation, and enhance multi-process efficiency in databases, operating systems, and cloud services.